3), It takes 129 J of work to move 1.8 C of charge from the negative plate to th

Question

3),

It takes 129 J of work to move 1.8 C of charge

from the negative plate to the positive plate

of a parallel plate capacitor.

What voltage di?erence exists between the

plates?

Answer in units of V

4

a). A pair of oppositely charged parallel plates is

separated by 5.57 mm. A potential di?erence

of 603 V exists between the plates.

What is the strength of the electric ?eld

between the plates? The fundamental charge

is 1.602

A charged cork ball of mass 1.6 g is suspended on a light string in the presence of a uniform electric field as shown. When the electric field has an x-component of 2.53 Times 105 N/C and a y-component of 3.92 Times 105 N/C, the ball is in equilibrium at 36.0514 Degree. Find the charge on the ball. The acceleration due to gravity is 9.8 m/s2 and the value of the Coulomb constant is

Explanation / Answer

1)

x direction:

T sin(theta) = q Ex

y direction:

T cos(theta) = m g - q Ey

dividing:

(T sin(theta))/(T cos(theta)) = (q Ex)/(m g - q Ey)

==> (sin(theta))/(cos(theta)) = (q Ex)/(m g - q Ey)

==> tan(theta) = (q Ex)/(m g - q Ey)

==> tan(30.0514) = (q * 2.53e5)/(1.6e-3*9.8 - q * 3.92e5)

==> 0.57855 = (q * 2.53e5)/(1.6e-3*9.8 - q * 3.92e5)

==> q = 18.9075e-9 C

==> q = 18.9 nC

-----------------------------------------------------------------------------------------

2)

T sin(theta) = q Ex

==> T = (18.9075e-9*2.53e5)/sin(30.0514)

==> T = 1.59 x 10^-4 N

-----------------------------------------------------------------------------------------

3)

V = E/q = 129/1.8 = 71.7 V

-----------------------------------------------------------------------------------------

4)

a)

-----------------------------------------------------------------------------------------

5)

k q/r = 380

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