The nucleus of a 125 X e atom (an isotope of the element xenon with mass 125 u )

Question

                    The nucleus of a 125Xe atom (an isotope of the element xenon with mass 125 u) is 6.0                     fm in diameter. It has 54 protons and charge q =+54e.                 

                    1,)What is the electric force on a proton 3.0fm from the surface of the nucleus?                     Hint: Treat the spherical nucleus as a point charge.                 

                    2.) What is the proton's acceleration?                 

Explanation / Answer

The total distance between a nucleus as a point charge and the proton is:

r = (6.0 x 10^-15 m) + (3.0 x 10^-15 m) = 9.0 x 10^-15 m

The charge of the nucleus is:

Q = 54 x (1.6 x 10^-19 C) = 8.64 x 10^-18 C

The electric force on the proton is:

F = kQq / r

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