(a) A cube with 1.40 m edges is oriented as shown in the figure in a region of u
ID: 2276153 • Letter: #
Question
(a) A cube with 1.40 m edges is oriented as shown in the figure in a region of uniform electric field. Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by 5.60i. (N*m(shift-6)2/C)
(b) Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -3.80j.
(c) Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -4.00i + 6.00k.
(d) What is the total flux through the cube for each of these fields?
A cube with 1.40 m edges is oriented as shown in the figure in a region of uniform electric field. Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by 5.60i. (N*m(shift-6)2/C) Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -3.80j. Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -4.00i + 6.00k. What is the total flux through the cube for each of these fields?Explanation / Answer
a) electric flux = E*A*cos(0) = 5.6*1.4^2 = 10.97 N.m^2/C
b) electric flux = E*A*cos(90) = 0
c) electric flux = E*A*cos(180)= 4*1.4^2*(-1) = -7.84 N.m^2/C
d) Net electric flux = Qin/epsilon
here Qinside = 0, so net electric flux = 0
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