In the figure below, a block of mass 5.00 kg is pulled along a horizontal fricti

Question

In the figure below, a block of mass 5.00 kg is pulled along a horizontal frictionless floor by a cord that exerts a force F = 10.1 N at an angle ? = 25.0

In the figure below, a block of mass 5.00 kg is pulled along a horizontal frictionless floor by a cord that exerts a force F = 10.1 N at an angle ? = 25.0 degree above the horizontal. What is the magnitude of the block's acceleration? The force magnitude F is slowly increased. What is its value just before the block is lifted (completely) off the floor? What is the magnitude of the acceleration of the block just before it is lifted (completely) off the floor?

Explanation / Answer

F=ma

a) Force=10.1 N.

Horizontal component =10.1cos25

=9.154

9.154=(5)a
a=1.83ms^-2

b) For the object to e lifted Fsin25 must be equal to weight
weight=mg
=5*9.8=49N.
Fsin25=49
Force=115.9N.

c) Force=115.9N.
115.9cos25=ma
115.9cos25=5a

a=21ms^-1

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