1) The current in a series circuit containing a light bulb is 1.75 A and the pot

Question

1)The current in a series circuit containing a light bulb is 1.75 A and the potential difference across the light bulb is 12.7 V. Use Ohm's Law to find the resistance of the light bulb. ?

2)The current in a resistor and the potential difference across the resistor are tabulated and plotted. The slope of the 'Current vs. Voltage' graph is 0.239 A/V. The resistance of the resistor is ?

3) When two resistors are connected in parallel with a battery, _______.

a) the power dissipated by each resistor is the same

b) the current in each resistor is the same    

Explanation / Answer

1) V = IR
R = V/I = 12.7/1.75=7.26 ohms

2) V = I R
so I = 1/R V
so slope = 1/R

R = 1/0.239= 4.18 ohms

3) d)

4) v ohm jack

5)
b) device, material

6) a) resistance

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