a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50
ID: 2277406 • Letter: A
Question
a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50. (a) Out of every gallon of fuel this engine burns, what fraction is wasted (i.e., produces energy that is wasted)?0% 42.4% 57.5% 100%
b)If you could change the compression ratio to 10.0 instead, what percentage of the fuel would be wasted?
100% 0% 39.8% 60.2% a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50. (a) Out of every gallon of fuel this engine burns, what fraction is wasted (i.e., produces energy that is wasted)?
0% 42.4% 57.5% 100%
b)If you could change the compression ratio to 10.0 instead, what percentage of the fuel would be wasted? a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50. (a) Out of every gallon of fuel this engine burns, what fraction is wasted (i.e., produces energy that is wasted)?
0% 42.4% 57.5% 100%
b)If you could change the compression ratio to 10.0 instead, what percentage of the fuel would be wasted? a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50. (a) Out of every gallon of fuel this engine burns, what fraction is wasted (i.e., produces energy that is wasted)?
0% 42.4% 57.5% 100%
b)If you could change the compression ratio to 10.0 instead, what percentage of the fuel would be wasted? a) An Otto engine uses a gas having ? = 1.40 and has a compression ratio of 8.50. (a) Out of every gallon of fuel this engine burns, what fraction is wasted (i.e., produces energy that is wasted)?
0% 42.4% 57.5% 100% 0% 0% 0% 42.4% 42.4% 42.4% 57.5% 57.5% 57.5% 100% 100% 100%
b)If you could change the compression ratio to 10.0 instead, what percentage of the fuel would be wasted? 100% 0% 39.8% 60.2% 100% 0% 39.8% 60.2% 100% 100% 100% 0% 0% 0% 39.8% 39.8% 39.8% 60.2% 60.2% 60.2%
Explanation / Answer
A)
Compression ratio = (P2/P1) = 8.5
y = specific heat ratio = 1.4
efficiency = { 1 - {1 / (P2/P1)^[(y-1)/y] }} = { 1 - {1 / (8.5)^ [(1.4 - 1)/1.4 ] }}
efficiency = 0.4574 = 45.74%
Waste fraction = 1 - 0.4574 = 0.5426 = 54.26%
Out of 1 gallon of fuel burns, there is 0.5426 gallon of fuel is wastes.
B)
Same procedure as part A but (P2/P1) = 10
eff. = {1 - {1 / (10)^[(1.4-1)/1.4] }} = 0.4820 = 48.20%
Waste fraction = 1 - 0.4820 = 0.518 = 51.8%
Out of 1 gallon of fuel burns, there is 0.518 gallon of fuel is wastes.
Final Answers : (rounding to nearest)
A) 57.5%
B) 60.2%
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