1) 2) 3) 4) 5) 6) A car is traveling around a horizontal circular track with rad

Question

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A car is traveling around a horizontal circular track with radius r = 270 m as shown. It takes the car t = 66 s to go around the track once. The angle ?A = 19degree above the x axis, and the angle ?B = 57degree below the x axis. 1) What is the magnitude of the car's acceleration? 2) What is the x component of the car's velocity when it is at point A 3) What is the y component of the car's velocity when it is at point A 4) What is the x component of the car's acceleration when it is at point B

Explanation / Answer

w=2pi/66 = 0.0952 rad/s.

speed (v)= w*r = 0.0952*270 = 25.704 m/s.

1)accelaration(A)= v^2/r =2.447 m/s^2.

2)Vx = -V*sin(theta a)= -8.368 m/s.

3)Vy = V*cos(theta a)= 24.3m/s

4)Ax = -Acos(theta b)=-1.33 m/s^2

5)Ay= A sin(theta b)= 2.05 m/s^2.

6)increasing

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