Consider a current I that flows in a plane rectangular current loop with height
ID: 2278180 • Letter: C
Question
Consider a current I that flows in a plane rectangular current loop with height a = 4.00cm and horizontal sides b = 2.00cm . (Figure 1) The loop is placed into a uniform magnetic field B? in such a way that the sides of length a are perpendicular to B? , and there is an angle ? between the sides of length b and B? , as shown in the figures. (Figure 2)
C) Assume that the current flowing into the loop is 0.500A . If the magnitude of the magnetic field is 0.300T , what is ?, the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field?
Consider a current I that flows in a plane rectangular current loop with height a = 4.00cm and horizontal sides b = 2.00cm . (Figure 1) The loop is placed into a uniform magnetic field B? in such a way that the sides of length a are perpendicular to B? , and there is an angle ? between the sides of length b and B? , as shown in the figures. (Figure 2) Assume that the current flowing into the loop is 0.500A . If the magnitude of the magnetic field is 0.300T , what is ?, the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field? Express your answer in newton-meters.Explanation / Answer
The max torgue is found when loop runs parallel to the field. In this case, we have an angle, ?, and we will need the component along the loop. Since it is adjacent to the loop, we will need to use the cos of the angle
Since ? = BIA, and we need the cos component of the B field, the equation becomes, ? = B(cos?)IA
Since you did not provide the values for a and b, the Area can not be calculated, but we can represent it
A = (ab)
we also don't have the value for the angle, so the best I can do is this...
? = (.3)(cos ?)(.5)(ab) or ? = (.15)(cos ?)(ab)
If you have the values for ?, a and b, just plug them in to get the final answer
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