Two different simple harmonic oscillators have the same natural frequency (f=4.8

Question

Two different simple harmonic oscillators have the same natural frequency (f=4.80 Hz) when they are on the surface of the Earth. The first oscillator is a vertical spring and mass, the second is a pendulum. If both systems are moved to the surface of the moon (g=1.67 m/s2), what is the new frequency of the pendulum?
1.98 Hz

Calculate the new frequency of the vertical spring and mass.

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Two different simple harmonic oscillators have the same natural frequency (f=4.80 Hz) when they are on the surface of the Earth. The first oscillator is a vertical spring and mass, the second is a pendulum. If both systems are moved to the surface of the moon (g=1.67 m/s 2), what is the new frequency of the pendulum? 1.98 Hz Calculate the new frequency of the vertical spring and mass.

Explanation / Answer

f = (1/2?)*?[g/L] which shows that
frequency varies directly with the ? of g:
Ergo,

fm = fe*?[gm/ge] = 4.80*?[1.67/9.8] = 1.98 Hz

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