Question Part Points Submissions Used Question Part Points Submissions Used Ques

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Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used (a) What does the balance read when the elevator is ascending with a constant speed of 29 m/s?
...................N

(b) What does the balance read when the elevator is descending with a constant speed of 29 m/s?
.................N

(c) What does the balance read when the elevator is ascending at 26 m/s and gaining speed at a rate of 13 m/s2?
................N
(d) Suppose that from t = 0 to t = 4.9 s, the elevator ascends at a constant speed of 10 m/s. Its speed is then steadily reduced to zero during the next 3.9 s, so that it is at rest at t = 8.8 s. Describe the reading of the scale during the interval 0 < t < 8.8 s.
T0 ? 4.9 = ............................N T4.9 ? 8.8 = ............................N Question Part Points Submissions Used A 2.00 kg block hangs from a spring balance calibrated in Newtons that is attached to the ceiling of an elevator. What does the balance read when the elevator is ascending with a constant speed of 29 m/s? What does the balance read when the elevator is descending with a constant speed of 29 m/s? What does the balance read when the elevator is ascending at 26 m/s and gaining speed at a rate of 13 m/s2? Suppose that from t = 0 to t = 4.9 s, the elevator ascends at a constant speed of 10 m/s. Its speed is then steadily reduced to zero during the next 3.9 s, so that it is at rest at t = 8.8 s. Describe the reading of the scale during the interval 0

Explanation / Answer

a) W = m*g = 2*9.8 = 19.6 N

b) W = m*g = 2*9.8 = 19.6 N

c) W = m*(g+a) = 2*(9.8+13) = 45.6 N

d) T0-4.9 = m*g = 2*9.8 = 19.6 N

T4.9-8.8 = m*(g-a) = 2*(9.8 - 10/3.9) = 14.47 N

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