I got A and part of B right but i cant figure out the resistance at the top and

Question

I got A and part of B right but i cant figure out the resistance at the top and bottom of the loop and the total power delivered to the combination, can someone help?

Three 100 ? resistors are connected as shown in the figure. The maximum power that can safely be delivered to any one resistor is 28.0 W.

resistor on the left W resistor at the top of the loop
How is the current through this resistor related to that of the leftmost resistor? What does that imply about the ratio of the powers delivered to the two resistors? W resistor at the bottom of the loop
You are correct that the power delivered to this resistor is the same as the power delivered to the top resistor. W I got A and part of B right but i cant figure out the resistance at the top and bottom of the loop and the total power delivered to the combination, can someone help? Three 100 ? resistors are connected as shown in the figure. The maximum power that can safely be delivered to any one resistor is 28.0 W. What is the maximum potential difference that can be applied to the terminals a and b? For the voltage determined in part (a), what is the power delivered to each resistor? What is the total power delivered to the combination of resistors? The total power delivered to a combination of resistors will be the same if the set of resistors is replaced by a single resistor with a resistance equal to the equivalent resistance. W

Explanation / Answer

A higher current would flow through the first resistor as compared to the other.

So,

28.0 W must be dissipated in first and design haas to be as per that.

P = I^2 * R

28 = I^2 * 100

I^2 = 0.28

I = 0.5291 A

V = IR = 52.91 V across first resistor

Across the parallel combination, half the current flows through each resistor

I = 0.2645

V = 26.45 V

Thus, maxmum total potential applied = 52.91 + 26.45 = 79.36V

Total power delivered to the combination = sum of power n each resistor

Single 100 ohm resistor, P1 = 28 W

Parallel resistors, P2 = 28 / 4 = 7W in each (since as the current halves, the power reduces to 1/4th )

Thus, total power = 28 + 7 + 7 = 42 W is the total power dissipation

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