The circuit in the figure below contains two resistors, R 1 = 3.00 k? and R 2 =

Question

The circuit in the figure below contains two resistors, R1 = 3.00 k? and R2 = 4.00 k?, and two capacitors, C1 = 3.00 ?F and C2= 4.00 ?F, connected to a battery with emf ? = 120 V.

a) If no charges exist on the capacitors before switch S is closed, determine the charge on capacitor q1 1.00 ms after the switch is closed.

b) Determine the charge on capacitor q2 1.00 ms after the switch is closed.

The circuit in the figure below contains two resistors, R1 = 3.00 k? and R2 = 4.00 k?, and two capacitors, C1 = 3.00 ?F and C2= 4.00 ?F, connected to a battery with emf ? = 120 V. If no charges exist on the capacitors before switch S is closed, determine the charge on capacitor q1 1.00 ms after the switch is closed. Determine the charge on capacitor q2 1.00 ms after the switch is closed.

Explanation / Answer

For charging capacitor;The total charge flowing in the circuit is given by;

Q=Ceq*V(1-e^(-t/T)

WHERW;

T=Req*Ceq (Ceq&Req are equivalent capacitance and resistance)

Now,

Ceq=C1+C2=7uf

Req=R1R2/R1+R2=12/7Kohm

Now at t=1ms

Q=7*120(1-e^(-10^-3/12/7*10^3*7*10^-6))

or

Q=67.16uC

Now this charge get distributed as in parallel connection given by;

Q1=(C1/C1+C2)*Q=28.78uC

Q2=(C2/C1+C2)*Q=38.38uC

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