In a truck-loading station at a post office, a small 0.200- k g package is relea
ID: 2279677 • Letter: I
Question
In a truck-loading station at a post office, a small 0.200-kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (the figure (Figure 1) ). The size of the package is much less than 1.60 m, so the package can be treated as a particle. It slides down the track and reaches point B with a speed of 5.00m/s . From point B, it slides on a level surface a distance of 3.00m to point C, where it comes to rest.
In a truck-loading station at a post office, a small 0.200-kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (the figure (Figure 1) ). The size of the package is much less than 1.60 m, so the package can be treated as a particle. It slides down the track and reaches point B with a speed of 5.00m/s . From point B, it slides on a level surface a distance of 3.00m to point C, where it comes to rest. What is the coefficient of kinetic friction on the horizontal surface? How much work is done on the package by friction as it slides down the circular arc from Ato B?Explanation / Answer
Kientic energy of the package at B = 1/2mv^2.
It is lost in doing work against frictional force F = F*s = 3F
F = 0.5mv^2/ 3 = (0.5*0.2*5*5/3) = 0.8333333 N
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2.
P,E at the top mgh
This is used up in giving k.e to the package and work against friction.
Work against friction = mgh - 0.5mv^2
h = radius of the path.
(0.2*9.8*1.6) - (0.5*0.2*5*5) = 0.636 J
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