physics A cable is lifting a construction worker and a crate, as the drawing sho
ID: 2280283 • Letter: P
Question
physics
A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 823 N and 1710 N, respectively. The acceleration of the cable is 0.620 m/s2, upward. What is the tension in the cable (a) below the worker and (b) above the worker?
Explanation / Answer
From the weights given you can calculate the masses:
m (worker) = 823N/(9.8m/s2) = 83.98kg
m (crate) = 1710N/(9.8m/s2) = 174.49kg
If the cable (and crate & worker) are being accelerated against gravity, then you have to add that acceleration to gravitational acceleration to get the tension).
Below the worker, the cable is pulling against only the crate, so the tension there is simply:
Tbelow = 1710N + (174.49kg)*(0.62m/s^2) = 1818.18 N
Above the worker the cable is pulling against both the worker and the crate (supporting both) so the tension there is:
T(above) = 1710N + 823N + (174.49kg)*(0.62m/s2) + (83.98kg)*(0.62m/s2)
= 2,693N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.