In the circuit on the right, a light bulb, two batteries, and five resistors are

Question

In the circuit on the right, a light bulb, two batteries, and five resistors are wired to form a circuit. For the following question, assume the color codes on resistors are not accurate (that is, use stated values) and assume each battery has 3.75 ? of internal resistance.

If the internal resistance of the light bulb is 327 ?, calculate the power dissipation of the bulb.

In the circuit on the right, a light bulb, two batteries, and five resistors are wired to form a circuit. For the following question, assume the color codes on resistors are not accurate (that is, use stated values) and assume each battery has 3.75 ? of internal resistance. If the internal resistance of the light bulb is 327 ?, calculate the power dissipation of the bulb.

Explanation / Answer

we have to find the current trough the bulb...

so,

consider the loop in which bulb is connected...

let current is through it is i

applying KVL

1 = 135*i+327*i+3.75i ..

1 = 465.75*i

==> i = 1/465.75 = 0.0021471

so,

power dissipation of the bulb = I^2*R = 0.0021471^2*327 = 0.00151 watt

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