A BMW of mass 1.9 103 kg is traveling at 42 m/s. It approaches a 1.1 103 kg Volk

Question

A BMW of mass 1.9 103 kg is traveling at 42 m/s. It approaches a 1.1 103 kg Volkswagen going 24 m/s in the same direction and strikes it in the rear. Neither driver applies the brakes. Neglect the relatively small frictional forces on the cars due to the road and due to air resistance. If the collision slows the BMW down to 36 m/s, what is the speed of the VW after the collision? During the collision, which car exerts a larger force on the other, or are the forces equal in magnitude? Volkswagen exerts the larger force. Forces are equal in magnitude. BMW exerts the larger force.

Explanation / Answer

a) m1= BMW

m1 *u1 + m2* u2 = m1*v1 + m2*v2

1900 * 42 + 1100 * 24 = 1900 * 36 + 1100 *v2

v2 = (106200 - 68400)/1100 = 34.36m/s

b) By Newton's third law of motion, the two cars exert equal and opposite force on each ohter

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