Two 1.90 c m -diameter disks spaced 1.80 m m apart form a parallel-plate capacit

Question

Two 1.90cm -diameter disks spaced 1.80mm apart form a parallel-plate capacitor. The electric field between the disks is 4.70

Two 1.90cm -diameter disks spaced 1.80mm apart form a parallel-plate capacitor. The electric field between the disks is 4.70 x 105V/m. Part A What is the voltage across the capacitor? Part B How much charge is on each disk? Part C An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.20 x 107m/s. What was the electron's speed as it left the negative plate?

Explanation / Answer

c = A*e/L

A = pi *r*r

l = 1.8mm

so, C = 1.46 x10^-16F

1. voltage = E*L = 846V

2. cherge = c*v = 1.23 x 10^-13C

3. 1/2*m*vf^2 = 1/2*m*vi^2 + V*q

    vf = 2.2x 10^7m/s

m = 9.1x 10^-31kg

so, vi = 1.36 x 10^7m/s

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