A projectile is launched straight up at 51.5 m/s from a height of 88.5 m, at the

Question

A projectile is launched straight up at 51.5 m/s from a height of 88.5 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below.

(a) Find the maximum height of the projectile above the point of firing. m

(b) Find the time it takes to hit the ground at the base of the cliff.

Your response differs from the correct answer by more than 100%. s

(c) Find its velocity at impact.

Is the velocity up or down at impact? Is that direction positive or negative? m/s

Explanation / Answer

Vy = 51.5 m/s

at highest point v = 0

a = -9.8 m/s2

h =( v2 -vy2)/2a = 135.32 m

b) y = -88.5 m

y = vyt + 0.5 at2

-88.5 = 51.5t - 4.9t2

t= 12.01 s

c) v = vy +at

v = -66.1m/s

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