Consider two point charged objects separated by a distance of 5.00 cm. The charg

Question

Consider two point charged objects separated by a distance of 5.00 cm. The charge on the left hand object is +36.0 ?C. The charge on the right hand object is -36.0 ?C. What is the strength (magnitude) of the electric field due to the left hand object only at the location exactly halfway in between the two charged objects? Incorrect. Tries 1/10 Previous Tries What is the strength (magnitude) of the electric field due to the right hand object only at the location exactly halfway between the two charged objects? Tries 0/10 What is the strength of the net electric field due to the BOTH objects at the point halfway between the two charged objects? Tries 0/10 What would be the force on a proton placed at the point halfway between the objects?

Explanation / Answer

E = kq/r2

1.    here E = k( 36.0 *10-6/ .0252 + 36.0 *10-6/ .0252)

E = 518400 N/C

2. E = k( 36.0 *10-6/ .0252 + 36.0 *10-6/ .0252)

net electric field in betweeb lines = 0 N/C

3. force on proton = qp*E

F = 1.6*10-19*518400

F = 8.294*10-14 N

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