This is about the reaction between acetic acid and an unknown alcohol with heat

Question

This is about the reaction between acetic acid and an unknown alcohol with heat and an acid catalyst.

r esterification has limitations because it rarely will convert 100 % of the starting you could use that 1. The Fishe product. Give an alternative reaction (ie, not Fisher conditions) should give 100 % conversio acid, and acid common, otherwise you better have a reference. n to the ester product. Note: do not just use an alcohol. carboxytie catalyst. Again- if necessary, search the internet - be sure the procedure enriched with 170 e out the chemical reaction for this experiment - as if you had an alcohol that was atoms in the alcohol. Be sure to account for all atoms. 3. Analysis by NMR during a reaction can be difficult because of the number of molecules If a small aliquot of the reaction mixture in this experiment were taken and added to Cl, to run an NMR, what can you say about the following information: triplet around 4.10 ppm integrates for 3 triplet around 3.75 ppm integrates for 2 singlets around 2.10 ppm integrate for a total of 7.5 CDCI to other peaks irrelevant... n the format of ratio of alcoo:estr acid, state the molar equivalents of these compounds 2 5 :NA (ie, there's 3 molecules of ester for every ex. molecule of alcohol but you can't tell how much acid remains) If you need to, use the chart at the back - specifically, look at ethyl acetate and try to learn from this what information can be gathered

Explanation / Answer

Answer for question 1

R'OH + CH3COOH + CH3COCl =   CH3COOR'  

This reaction will give 100% yield, as in the presence of CH3COCl (used as catalyst) , reaction is irreversible.

In case of Fischer esterification, reaction is revesible.

Answer for question 2

R'O17H + CH3COOH +  CH3COCl =   CH3COO17R' + H2O

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