Shooting over a Hil Part A A projectile is fired with speed Ul at an angle from
ID: 2283320 • Letter: S
Question
Shooting over a Hil Part A A projectile is fired with speed Ul at an angle from the horizontal as shown in the figure (Figure 1) Find the highest point in the trajectory, H Express the highest point in terms of the magnitude of the acceleration due to gravity g, the initial velocity 10, and the angle Submit Hints My Answers Give Up Review Part Part B What is the range of the projectile, R? Express the range in terms of U, , and g. Submit Hints My Answers Give Up Review Part Consider your advice to an arti lery officer who has the following problem. From his current postition, he must shoot over a hill of height F at a target on the other side which has the same elevation as his gun. He knows from his accurate map both the bearing and the distance R to the target and also that the hill is halfway to the target To shoot as accurately as possible, he wants the projectile to ust barely pass above the hi Fgure 1 of 1 Part C Find the angle above the horizontal at which the projectile should be fired. Express your answer in terms of H and R. Submit Hints My Answers Give Up Review Part Part DExplanation / Answer
PART A
Highest point in the trajectory is , H= v02sin2 theta/2g
PART B
Range of the projetile, R= V02sin[ 2* theta] /g
PART C
Taking equation of H and R
we have ,vo2= 2Hg / sin2 theta and vo2= Rg/sin[ 2* theta]
plugging 2Hg / sin2 theta= Rg/sin[ 2* theta]
we get ,Theta = arctan (4 H / R)
PART D
Taking equation of H and R
we have ,vo2= 2Hg / sin2 theta
And
vo2= Rg/sin[ 2* theta]
PART E
Time of flight, T= 2Vo sin theta/ g
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