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1) 2) 3) Enter vour answer in scientific notation In 1911, Ernest Rutherford dis

ID: 2283527 • Letter: 1

Question

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3)

Enter vour answer in scientific notation In 1911, Ernest Rutherford discovered the nucleus of the atom by observing the scattering of helium nuclei from gold nuclei. If a helium nucleus with a mass o6.68 x 1027 kg, a charge of +2e, and an initial velocity of 1.50 × 107 m/s is projected head-on toward a gold nucleus with a charge of +79e, how close will the helium atom come to the gold nucleus before it stops and turns around? Assume the gold nucleus is held in place by other gold atoms and does not move. 10 Gelect) x 10 (select)

Explanation / Answer

1) Ei = Ef

1/2 mv^2 = k 2e 79 e/r

9.0E9*2*79*1.6E-19^2/r = 0.5*6.68E-27*1.5E7^2

r= 4.84E-14 m

2) so F electric = m g

q E = m g

q = mg/E = 2.0E-15*9.81/1.53E4= 1.28E-18 C

3) V = sum of k q/r = 9.0E9*2.0E-3/4 + 9.0E9*-6.0E-3/5=-6.3 MV

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