A satellite in outer space is moving at a constant velocity of 21.2 m/s in the +

Question

A satellite in outer space is moving at a constant velocity of 21.2 m/s in the +y direction when one of its onboard thruster turns on, causing an acceleration of 0.300 m/s2 in the +x direction. The acceleration lasts for 44.0 s, at which point the thruster turns off.

(a) What is the magnitude of the satellite's velocity when the thruster turns off?
m/s

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

Explanation / Answer

vy = 21.2

vx = 0.3*44

mag = sqrt(vx^2 + vy^2) = sqrt(21.2^2 + (0.3*44)^2)= 24.97 m/s

b) direction = arctan(vy/vx) = arctan(0.3*44/21.2)= 31.9 degrees

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