Answer the following questions using info manual. The responses will be collecte

Question

Answer the following questions using info manual. The responses will be collected at the of your lab section for credit. 1. For a weak acid HA in aqueouss obtained from lecture, the textbook, or lab ginning of recitation and checked at the start , or lab on described by HA(aq) + H,00% H30.(aq) + 0 A (aq), the equilibrium constant is given by fboth sides ofthe equation andrearrange to derive t he Henderson-Hasselbalch Recall that pH =-log [H301 and pKf-log K . Show details ofyour derivation our final derived form of the Henderson-Hasselbalch equation below and box y 127

Explanation / Answer

Ka = [H30+] [A-] / [HA]

Ka / [H30+] = [A-] / [HA]

now apply logarithm on both sides

log ( Ka / [H30+]) = log [A-/HA]

now by definition , log (a/b) = log a - log b

so

log Ka - log [H30+] = log [A-/HA]

-log [H30+] = -log Ka + log [A-/HA]

now by definition , -log [H30+] = pH and -log Ka = pKa

plug in those values to get

pH = pKa + log ([A-]/[HA] )

this is Hasselbalch hendersen equation

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