A car travels along a straight line at a constant speed of 61.0 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 61.0 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 33.5 mi/h.

(a) What is the constant speed with which the car moved during the second distance d?



(b) Suppose the second distance d were traveled in the opposite direction; you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip?
mi/h

(c) What is the average speed for this new trip?
mi/h

Explanation / Answer

average velocity = 2d/total time = 33.5

totaltime = d/61 + d/v

so

2d/(d/61 + d/v) = 33.5

2/(1/61 + 1/v) = 33.5

v=23.09 mi/hr

b)

since it went back to the same point, displacement = 0

then average velocity = 0

c) average speed = 33.5 mi/hr

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