A 124-kg balloon carrying a 22-kg basket is descending with a constant downward

Question

A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 11.0m/s A 1.0-kg stone is thrown from the basket with an initial velocity of 15.6m/s perpendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. The person in the basket sees the stone hit the ground 6.70s after being thrown. Assume that the balloon continues its downward descent with the same constant speed of 11.0m/s .

I need answers with same numbers that I have ...

Part A

How high was the balloon when the rock was thrown out?

Part B

How high is the balloon when the rock hits the ground?

Part C

At the instant the rock hits the ground, how far is it from the basket?

Part D

Just before the rock hits the ground, find its horizontal and vertical velocity components as measured by an observer at rest in the basket.

Part E

Just before the rock hits the ground, find its horizontal and vertical velocity components as measured by an observer at rest on the ground.

Explanation / Answer

A) ho = voy*t + 0.5*g*t^2

= 11*6.7 + 0.5*9.8*6.7^2

= 293.66 m

B) h1 = Ho - voy*t

= 193.66 - 6.7*11

= 219.96 m

c) x = vox*t

= 15.6*6.7

= 104.52

r = sqrt(h1^2+x^2)

= sqrt(219.96^2 + 104.52^2)

= 243.52 m

d) vx = vox = 15.6 m/s

vy = g*t

= 9.8*6.7

= 65.66 m/s

e) vx = 15.6 m/s

vy = 11 + g*t

= 11 + 65.66

= 76.66 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.