Consider a point charge q=10^-6 C. a) What is the flux (Phi) passing through a s

Question

Consider a point charge q=10^-6 C.
a) What is the flux (Phi) passing through a spherical shell of radius R=10 cm with the point charge at its center?
b) What is the flux (Phi) passing through a spherical shell of Radius R=1 m with the point charge at its center?
Hint: For the simple charge, the electric field is in the radial direction ??? , which is exactly the same as the normal to the surface (the spherical shell) ??? . Also, the electric field is constant on the shell (since the shell represents a constant value of r=R, R is a constant). The electric field of a simple charge at distance r from the charge : ??(??) = ???? ???. ??2 ?Given: - ?????????= ? (??h?????? ???? ???????????? ??) ? ??(??).??????? - ? ???? for a spherical shell of radius R = area of spherical shell = 4????2

Explanation / Answer

Given that,

The point charge at the centre is,q=10^-6C

The flux through the spherical shell is,

phi=EA=Q/epsilonnot

phi=Q/4*pi*epsilonnot*R^2

a)The Radius of the spherical shell is,R=10cm

Then the flux is,

phi=10^-6*9*10^9/100*10^-4

phi=9*10^5

b)The radius of the spherical shell given by,

R=1m

phi=Q/4*pi*epsilonnot*R^2

phi=10^-6*9*10^9/1

phi=9*10^3

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