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Three resistors having resistances of R 1 = 1.61?, R 2 = 2.44? , and R 3 = 4.78?

ID: 2289903 • Letter: T

Question

Three resistors having resistances of R1 = 1.61?, R2 = 2.44? , and R3 = 4.78? respectively, are connected in parallel to a 28.5V battery that has negligible internal resistance.

Part A:

Find the equivalent resistance of the combination.

Part B:

Find the current in each resistor.

Part C

Find the total current through the battery.

I= A

Part D

Find the voltage across each resistor.

VR1,VR2,VR3= V

Part E

Find the power dissipated in each resistor.

PR1,PR2,PR3 = W

Show Work Please!

Find the current in each resistor.

Req =
?  

Explanation / Answer

part a)

let R be the equivalent resistence

1/R=1/R1+1/R2+1/R3

part b)

now V is given , and it is same for all the resistences

I1=V/R1

I2=V/R2

I3=V/R3

part c)

total current I=I1+I2+I3

part d)

Voltage across each reistor

V1=V2=V3=V

part e)

P1=VI1

P2=VI2

P3=VI3

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