In the figure, a block of mass m = 4.25 kg is pulled along a horizontal friction
ID: 2290364 • Letter: I
Question
In the figure, a block of mass m = 4.25 kg is pulled along a horizontal frictionless floor by a cord that exerts a force of magnitude F = 14.8 N at an angle Theta = 22.0 Degree. (a) What is the magnitude of the blocks acceleration? (b) The force magnitude F is slowly increased. What is its value just before the block is lifted (completely) off the floor? (c) What is the magnitude of the blocks acceleration just before it is lifted (completely) off the floor? (a) Number Units (b) Number Units (c) Number UnitsExplanation / Answer
1) F cos 22 = ma
14.8cos22 = 4.25 a
a= 3.23 m/s2
2) mg - F sin (theta)= N ............... eqn 1
for lifting the mass N=0
SO F= 4.25*9.8/sin22 = 111.8 N
3) a= F cos22/4.25
a= 111.8 cos22/4.25 = 24.39 m/s2
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