Name Date Construction of an Electric Motor Experiment: To construct and underst
ID: 2291180 • Letter: N
Question
Name Date Construction of an Electric Motor Experiment: To construct and understand the principles underlying the operation of an electric motor Apparatus 1 Horseshoe agnet 2 Thumbtacks 1 Piece of woodenb lock 1 Long-nose pliers I piece of sandpaper 2 Paper clips 1 Insulated wire 50 cm long 1 D-size flashlight batteries 2 Wires with magnet ends (1) Loop the insulated wire around the D-size battery to make a coil. Pull out the wire ends from the opposite side of the coil, loop the ends around the coil 2 3 times to keep the loose windings together Use the paper clips as brackets. They are fastened to The coil will be supported by the paper clips. (2) Make a support for the coil. the wooden block with thumbtacks. One such support is schematically shown in the figure below Csi (3) Now comes the hardest part. The insulation on the two ends of the coil on contact with the paper clips must be removed. This can be done with some sandpaper or scraped off with a knife or scissor blade. However, if you remove the insulating material all the way around the wire on both ends, the motor will not continue to rotate. A "commutator" is needed. One solution is to remove the insulating material on only one "half" from each end. (See the figure on next page, whichExplanation / Answer
6. The coil spins in clockwise direction.
7.yes.Step 6 observation match with this rule.Magnetic Torque is directly proportional to field flux and armature current.
8.We can make the motor spin faster by piling of several magnets together to increase the strength of Bfield.
9.By holding a magnet over the top of the motor,that is by moving the magnet closer to the spinning coil with correct position that is by hoding the motor down sso that the magnets will not jump together and will not get crushed.This will help you to make motor run faster.
10.1.Number of loops of the coil=L/2*3.14*r
=>50cm/(2*pi*1.025*10^-3)
=>155 turns
10.2.Resistance of the wire=Resistivity*Length of the wire/Area of each loop
=>R=1.7*10^-8*50*10^-2/8.31*10^-4
=>10.22*10^-6ohm
10.3.Imax=Battery voltage/Resistance of th wire
=>1.5/10.22*10^-6
=>0.15MA
10.4.maximum magnetic torque=Imax *N*B*A(loop)
=0.15*10^6*150*10^-6*155*8.31*10^-4
=2.898Nm.
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