XEG1 R1 2 C1 0.01uF Vout 0 is the time constant in seconds). Time constant (RC)-

Question

XEG1 R1 2 C1 0.01uF Vout 0 is the time constant in seconds). Time constant (RC)- Use transient analysis to observe both the input and output of the RC voltage divider. Make a printout of the output. Record how much time it takes for the capacitor to fully charge. (When the capacitor is fully charged the voltage across it will equal the input voltage.) Measured time constant- Compare the time required to charge the capacitor found with the RC time constant. How many RC time constants are required to fully charge up the capacitor? Time to fully charge Part 2: Change the square wave to 1 kHz and readjust the transient analysis to observe the output. Attach the output. Describe what you think is happening. Is there enough time for the capacitor to charge up?

Explanation / Answer

Time constant (RC) = 51 x 103 x 0.01 x 10-6

= 51 ms

Time constant required to fully charge a capacitor is 5 time constants.

So,

Time to fully charge = 5 x 51 ms = 255 ms

Part 2.

If square wave is applied then voltage drop across alternates between charging & discharging. So, in this case to fully charge a capacitor 10 time constant is required.

So, time needed will be 10 x 51 ms = 510 ms

For 1 kHz , T = 1/f = 1/103 = 1ms

Since time period is less than 10 time constant. so, there is not enough time to fully charge the capacitor.

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