3. Connect V in to one channel of the oscilloscope and V out to the second chann

Question

3. Connect Vin to one channel of the oscilloscope and Vout to the second channel of the oscilloscope. Adjust the signal source at Vin to be a signal of 1 kHz at 0.5 VPP. Capture the input and output waveforms using print screen and insert them on the worksheet with proper caption. A typical scope display is shown below.

Answer the following questions on the worksheet.

What is the peak-to-peak voltage of Vin on the oscilloscope display?

What is the peak-to-peak voltage of Vout on oscilloscope display?

Are the Vin and Vout waveforms in phase or out of phase?

What is the calculated voltage gain (AV) of this circuit?

Can the voltage gain of a common-source amplifier be greater than 1? Why?

4. Reduce the setting of the DC source (VDD) to +9V as shown below. Note that if the peak of the waveform at Vout is clipped; reduce the input signal level until the clipping effect is no longer apparent. Capture the input and output waveforms using print screen and insert it on the worksheet with proper caption.

Answer the following questions on the worksheet.

What is the peak-to-peak voltage of Vin on the oscilloscope display?

What is the peak-to-peak voltage of Vout on the oscilloscope display?

What is the calculated voltage gain (AV) of this circuit?

Does decreasing the value of VDD increase the voltage gain?

Explanation / Answer

Hello,
          Please find the answer to the first question attached as under. Please give a thumbs up rating if you find the answer useful! Have a rocking day ahead!

1. Peak to Peak of Vin = Vmax - Vmin = 0.5 volts

2. Peak to Peak of Vout = Vmax - Vmin = 1.8 volts - (- 2 volts) = 3.8 volts

3. Vin and Vout are out of phase by 180 degrees.

4. Voltage gain = Vout (pp) / Vin(pp) = 3.8/0.5 = 7.6

5. The voltage gain of a common source amoplifier can be greater than one. The gain is partly determined by the transconductance of the amplifier, which again depends on the operating point. The gain also depends on the drain resistance. The total voltage gain is transconductance x drain resistance, which can always be set to greater than one.

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.