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Cengage x \', owLv2 | Online teaching and i × signment/takeCovalentActivity.do?l

ID: 229209 • Letter: C

Question

Cengage x ', owLv2 | Online teaching and i × signment/takeCovalentActivity.do?locator assignment-take&takeAssignmentSessionLocator; assignment-take Use the References to access important values if needed for this qu The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °c H2O2(aq) H20(I) + ½ O2(g) is first order in H202 with a rate constant of 1.10x10 min If the initial concentration of H202 is 4.46x10 M, the concentration of Hy0, will be 1.30x102 M after min have passed. Retry Entire Group 2 more group attempts remaining

Explanation / Answer

first - order :

rate constant k = 1.10 x 10^-3 min-1

initial concentration Ao = 4.46 x 10^-2 M

final concentration At = 1.30 x 10^-2 M

k = 1/t ln (Ao / At)

1.10 x 10^-3 = 1/t ln (4.46 x 10^-2 / 1.30 x 10^-2)

t = 1121 min

time taken = 1.12 x 10^3 min

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