I am having trouble understanding the solution to this problem can someone exlai

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I am having trouble understanding the solution to this problem can someone exlain each step thank you so much

Problem 2. (20 points) A 208V, 60 Hz six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: Locked rotor 24.6 V, 64.5 A, 2200 W, 15 Hz OC test 208 V, 22.0 A, 1200 W, 60 Hz 13.5 V, 64 A a. Sketch the per-phase equivalent circuit for this motor. (For Design Class B motor Xi-0.4 Xir and X-0.6 Xirwhere XiR is the locked rotor reactance at 60Hz) b. Find the induced torque and load torque; c. Find the machine efficiency; d. What's the operating speed of the motor if the induced torque is decreased by 25%? e. Find the slip at the pullout torque and find the value of the pullout torque itself. From the DC test, 2R = -R-0, 105 ? In the no-load test, the line voltage is 208 V, so the phase voltage is 120 V. Therefore X-X,-- - 5.455 ? @ 60 Hz In the locked-rotor test, the line voltage is 24.6 V, so the phase voltage is 14.2 V. From the locked-rotor test at 15 Hz, 64 V, 120 I 22 T. 14.20 0.2202 ? 220036.82 3 x24.6x 64.5 LR R,,-?z, l cos6,,-0.2202x cos 36.82°-0.1 76 RR 0176-R0.176-0.105 0.0712 XLR = RI snel,-0.2202x sin 36.82°-0. 132 ? At a frequency of 60 Hz, 60 For a Design Class B motor, the split is X,-02 11 ? and X,-0.317 ? X-5455-0.211-5.244 2 The resulting equivalent circuit is shown below:

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