in your unknown Sape. Questions 1. Calculate the molarity of a standard Ag\' sol

Question

in your unknown Sape. Questions 1. Calculate the molarity of a standard Ag' solution made by adding 0.8416 g of AgNO, to exactly 500.0 mL 2. 0.2500 g of a soluble chloride sample was dissolved in exactly 250.0 mL. It took exactly 40.00 ml of 001000 M Ag to titrate a 25.00 mL aliquot of the sample solution. Calculate the % CI, in the sample. 3. 3100 mL of a river water sample took 9.30 mL of 0.0100S M Ag to titrate. Calculate the concentration of CIT in ppm (ug/mL or mg/L) for the river water 4. Use the following date obtained with Ag/SCE electrodes for direct CI measurement to prepare a graph plot of mV vs. log CI concentration in ppm of standards. Use the graph equation for the straight line to determine the ppm Cr in the River water sample and 96 cr in the unknown cr sample Data m V reading 1000 ppm C 100 ppm Cl 10 ppm C 110 150 190 160 River water sample CT unknown (0.250 g sample in 100 mL) 120 5. Calculate the electrode potential for a silver filled electrode in a solution of 0.00550 M AgNO solution

Explanation / Answer

Ans 1

Moles of AgNO3 = mass/molecular weight

= 0.8416 g / 169.87 g/mol

= 0.004954 mol

Molarity = moles/Volume

= 0.004954 mol / 0.500 L

= 0.0099 M

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