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ID: 2294990 • Letter: #
Question
%3Cp%3E%3Cimg%20src%3D%0A%22webkit-fake-url%3A%2F%2F9C19F944-4909-4D83-ABF4-C0024DA1C171%2Fapplication.pdf%22%20%2F%3E%20%3Cspan%20class%3D%22c1%22%3EThe%0Acircuit%20shown%20in%20the%20figure%20is%20driven%20by%20a%2024-V%20battery%20(not%0Ashown).%20The%20battery%20is%20connected%20at%20the%20points%20A%20and%20B.%20The%20values%0Aof%20all%20the%20resistors%20are%20shown%20in%20the%20figure.%20(For%20clarification%2C%0Aone%20of%20the%20resistances%20is%20(10%2F3)%20ohms%3C%2Fspan%3E%3Cspan%20class%3D%0A%22c2%22%3E.%3C%2Fspan%3E%20%3Cspan%20class%3D%22c1%22%3EHow%20much%20power%20is%20dissipated%20in%20the%0A(10%2F3)%26nbsp%3B%3C%2Fspan%3E%3Cspan%20class%3D%22c1%22%3Eresistor%3F%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c1%22%3E%3Cbr%20%2F%3E%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c1%22%3EPlease%20show%20all%20work.%20Lifesaver%20will%20be%0Aawarded.%3C%2Fspan%3E%3C%2Fp%3E%0AExplanation / Answer
calcualte the thevinin resistance across the resitance at which power has to be calculated.
calculate the thevinin voltage across the same resistance.
now develope thevinin ckt ...
calculate the current in the thevinin ckt suppose it is " I"
then power consumed will be= I^2 x R
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