A 19.8 kg block is dragged over a rough, hor- izontal surface by a constant forc

Question

A 19.8 kg block is dragged over a rough, hor- izontal surface by a constant force of 180 N acting at an angle of angle 32.8? above the horizontal. The block is displaced 75.5 m and the coefficient of kinetic friction is 0.173. 19.8 kg ? = 0.173 Find the work done by the 180 N force. The acceleration of gravity is 9.8 m/s2 . Answer in units of J Find the magnitude of the work done by the force of friction. Answer in units of J Find the work done by the normal force. Answer in units of J What is the net work done on the block? Answer in units of J

Explanation / Answer

a) Workdone by applied force = F*s*cos(theta)

= 180*75.5*cos(32.8)

= 11423.3 J

b)

Workdone by friction = -N*mue*s

= (m*g - F*sin(32.8))*mue*s

= (19.8*9.8 - 180*sin(32.8))0.173*75.5

= -1260.8 J

c) Workdone by normal force = 0

d) Wnet = 11423.3 - 1260.8 + 0

= 10162.4 J

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