a. Find the potential energy of the skateboarder at position 1. b. Find the kine

Question

a. Find the potential energy of the skateboarder at position 1.

b. Find the kinetic energy of the skateboarder at position 1.

c. Find the mechanical energy of the skateboarder at position 1.

d. Find the potential energy of the skateboarder at position 2.

e. Find the speed of the skateboarder at position 2.

f. Position 3 represents the highest point the skateboarder reaches before coming back down the ramp. What is the kinetic energy of the skateboarder at this position?

g. What is the potential energy of the skateboarder at this position?

h. What is the height of the skateboarder at this position?

Explanation / Answer

As position 1 is zero point for potential energy,

Potential Energy =0

Kinetic Energy =mv2/2 =60*(5.42)/2 =874.8 J

=>Total Energy =874.8+0 =874.8 J

Position 2:

Potential Energy =mgh =60*10*1 =600 J

Conservation of Energy => Total Energy is always constant

Kinetic Energy = 874.8-600 =274.8 J =mv2/2 =60/2*v2

=>30v2 = 274.8 J => v= 3.03 m/s at position 2.

Position 3:

Here, Kinetic Energy =0 as velocity =0,

=>Potential Energy =mgh =Total Energy =874.8 J

=>60*10*h = 874.8 J

=>h = 1.46 m

which is the maximum height he can reach.

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