A meterstick (L = 1 m) has a mass of m = 0.133 kg. Initially it hangs from two s

Question

A meterstick (L = 1 m) has a mass of m = 0.133 kg. Initially it hangs from two short strings: one at the 25 cm mark and one at the 75 cm mark.

1) What is the tension in the left string right after the right string is cut?          

2) After the right string is cut, the meterstick swings down to where it is vertical for an instant before it swings back up in the other direction.

What is the angular speed when the meterstick is vertical?     

3) What is the acceleration of the center of mass of the meterstick when it is vertical?

4)    What is the tension in the string when the meterstick is vertical?

Explanation / Answer

other

Use the conservation formula you already have. D will be L/4 = 0.25 m, the change in the vertical distance of the center of mass. The moment of inertia (I) about the 0.25m mark would be, by parallel axis theorem:
I = mL

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