1. An ideal transformer has a primary with 25 turns and secondary with 15 turns.
ID: 2299216 • Letter: 1
Question
1. An ideal transformer has a primary with 25 turns and secondary with 15 turns. The load resistor is 24 ? and the source voltage is 85 Vrms.What is the rms electric potential across the 24 ? load resistor?
Answer in units of Vrms
2. A transformer consists of two coils of wire wound on a common toroidal iron core. The mutual inductance of the pair is 483 mH and the current in the first coil decreases from 29 A to 0 in 2.9 s.
What is the induced emf in the second coil? Answer in units of V.
3.If the outer coil has 14.7 turns, a radius of 19 cm and length of 7.47 cm and the inner coil has 628 turns, a radius of 7 cm, and a length of 33.3 cm, find the mutual inductance of the circular coil and solenoid.
Answer in units of ?H
4. Now the current in the solenoid is increased linearly at a rate of di/dt = a =20.2 A/s.
What is the magnitude of the voltage E across the circular coil?
Answer in units of ?V.
Explanation / Answer
1. An ideal transformer has a primary with 25 turns and secondary with 15 turns. The load resistor is 24 ? and the source voltage is 85 Vrms.What is the rms electric potential across the 24 ? load resistor?
V1/V2 = N1 / N2
so V2 = 85*15/25 = 51
so voltage across 24 ohms = 51 V rms
Answer in units of Vrms
2. A transformer consists of two coils of wire wound on a common toroidal iron core. The mutual inductance of the pair is 483 mH and the current in the first coil decreases from 29 A to 0 in 2.9 s.
What is the induced emf in the second coil?
V = M* di / dt = 483*0.001 8 ( 29-0) / 2.9 = 4.83 volts
Answer in units of V.
3.If the outer coil has 14.7 turns, a radius of 19 cm and length of 7.47 cm and the inner coil has 628 turns, a radius of 7 cm, and a length of 33.3 cm, find the mutual inductance of the circular coil and solenoid.
The mutual inductance = Uo*A1*ns*Nc = (note convert ns to turns per meter)
Uo*pi*0.07^2*628*100/33.3 *14.7 = 536.276579724 micro henry
Answer in units of ?H
4. Now the current in the solenoid is increased linearly at a rate of di/dt = a =20.2 A/s.
What is the magnitude of the voltage E across the circular coil?
E = M* di/dt = 536.276579724 * 0.000001 * 20.2 = 10832.7869104248 micro volts
Answer in units of ?V.
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