Two loudspeakers, 5.0m apart and facing each other, play identical sounds of the

Question

Two loudspeakers, 5.0m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.30m.

Part A

What is the frequency of the sound?

Express your answer using two significant figures in Hz.

PREVIOUS INCORRECT ANSWERS USED: 686 690 570 Hz

Part B

If the frequency is then increased while you remain 0.30m from the center, what is the first frequency for which that location will be a maximum of sound intensity?

Express your answer using two significant figures in Hz.

PREVIOUS INCORRECT ANSWERS USED: 1372, 1400 Hz

Explanation / Answer

Calculates the speed of sound 340 m / s as if.
(a) L1+L2= 5m
Ld= |L1-L2|= (2.5+0.3)-(2.5-0.3)=0.6m
Ld=?/2
?=2Ld =2*0.6= 1.2m
f=v/? =340/1.2= 283.33[Hz]
(b) 0.6=?
f=v/? = 340/0.6=566.6[Hz]

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