need to answer the following: LED light source. LED meters e an grating observe

Question

need to answer the following:

LED light source. LED meters e an grating observe and measure spectral lines produced by the electric discharge You Using the above setup in the lab you will light source. can find the angle by (i) measuring the separation x between equivalent lines (here "equivalent us values of the same order m and corresponding to the same means belonging to plus and min wavelength) and (ii) measuring the distance between the grating and the ruler, and (iii) using the formula for n the above figure. Once you have obtained 0 you can find the wavelength a of the line you are measuring. Enter below in MapleTA syntax the correct formula for doing this; use the substitution lambda for the wavelength of the line you are measuing d sin where m is an integer that gives the order of diffraction. with wavelength 664 nm en, using the spacing d that you calculated for the diffraction grating in Question 1, you can find what the above If you have a red line formula will give you for m 3 Enter that value. sin( 0 664 nm the highest order of the diffraction that can be seen with your setup has the at for a red spectral line with wavelength This means value m However, if we now consider a blue specta line with wavelength 450 nm then for m E 3 sin This means that for this blue spectral line the m difffraction maximum can be seen

Explanation / Answer

1)) d sin (th) = m*lambda ==> m integer, gives the order of diffraction

2)) sin (th)= m*lambda/d(spacing of diffraction grating) = 3 * 664nm/ d(= 1896 nm) = 1.05 >1 (max of sin(th))...

so you cant see the m=3 order

==> the highest order of diffraction that could be observed on the screen is m=2.

3)) for the blue light

sin (th)= m*lambda/d(spacing of diffraction grating) = 3 * 450nm/ d(=1896 nm) = 0.72 <1 (max of sin(th))...

so you can see the m=3 order

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