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Not really sure what formulas to use for this question. Thanks! A pair of conduc

ID: 2301810 • Letter: N

Question

Not really sure what formulas to use for this question. Thanks!

A pair of conducting, parallel rails arc separated by 12.0 cm and are connected at one end by a resistance R = 8.0 ohm as shown in the figure. A conducting bar is pulled along the frictionless rails with a constant velocity of 3.60 m/s. A uniform magnetic field B = 0.750T is directed out of page. What is the magnitude of the induced current? 1 =_ Is the direction of the induced current: Clockwise / counterclockwise / both: sinusoidal current is induced How much power is dissipated in the resistor? P(R) =_ How big is the pulling force? F =_ How much power docs the pulling force supply to the bar? P(Force) =

Explanation / Answer

A = l*b => dA/dt = bdl/dt = 3.6 b = 3.6 *12/100 = 0.43

Induced Emf = -NBdA/dt = -1 * 0.75 * 0.43 = -0.32 V

a) therefore, Induced current = 0.32/R = 0.32/ 8 = 0.04 A

b) clockwise

c) P = I2R = (0.04)2 * 8 = 0.013 W

d) pulling force => F- Fm = 0

F= Fm => Fm = I * B * L = 0.04 * 0.75 * 0.12 = 0.0036N

e) P = Pdissipated = 0.013W

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