Two capacitors are connected in parallel and connected to a 6V battery. Each cap

Question

Two capacitors are connected in parallel and connected to a 6V battery. Each capacitor has a plate area of 1cm2 and a plate separation of 1mm. They initially have a vacuum between the plates.

a) Calculate the capacitance of one of the capacitors and the total capacitance for the pair of capacitors.

b) Calculate the charge on each capacitor.

c) The capacitors are now disconnected from the battery (when fully charged) and a 1mm sheet of mylar (dielectric constant =3.30) is slipped between the plates of one of them. Calculate the new capacitance and the new voltage across the capacitor with mylar.

d) If the capacitors are now reconnected in parallel, determine the charge on each and the potential difference across them.

Explanation / Answer

a) C1 = C2 = eo*A/d = (8.84*10^-12*10^-4)/(10^-3) = 884e?15 F

Ceq = C1 + C2 = 1.768e?12 F

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b) in parallel combination V is same for both the capacitors

Q1 = C1*V = 5.304e?12 C

Q2 = C2*V = 5.304e?12 C

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c) C1' = Keo*A/d = k*C1 = 2.917e?12 F

V1' = V/k = 6/3.3 = 1.818 volts
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d) Ceq = C1' + C2 = 3.801e?12 F

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