A copper rod of length 0.92 m is lying on a frictionless table (see the drawing)

Question

A copper rod of length 0.92 m is lying on a frictionless table (see the drawing). Each end of the rod is attached to a fixed wire by an unstretched spring that has a spring constant of k = 76 N/m. A magnetic field with a strength of 0.18 T is oriented perpendicular to the surface of the table.

(a) What must be the direction of the current in the copper rod that causes the springs to stretch?

The current flows  ---Select--- left-to-right right-to-left in the copper rod.

(b) If the current is 14 A, by how much does each spring stretch?
m

Explanation / Answer

a) The current must be horizontally perpendicular to the spring and "positively" be perpendicular to the magnetic field.

b) Il x B = kx

IlB/k = (14A)(0.92m)(0.18T)/(76N/m) = 0.0305m

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