PHYS 2326 Spring 201!3 ???? 1-24-2013 Multiple Choices (1) When water warms from
ID: 2303575 • Letter: P
Question
PHYS 2326 Spring 201!3 ???? 1-24-2013 Multiple Choices (1) When water warms from 0 °C to 4 °C, the density of the water (a) increases (b) decreases. (c) remain constant. (d) becomes zero. e) none of the preceding. (2) If the work done by a system is equal to zero, the process is (a) isothermal (3) The number of molecules in one mole of a substance (b) adiabatic (c) isobaric (d) isometric (a) depends on the molecular weight of the substance. (b) depends on the density of the substance. (c) is the same for all substances (d) depends on the atomic weight of the substance. (e) depends on the temperature of the substance. (4) How many moles of H,0 molecules are in a 4.00 m container at a pressure 8.00 x 10 N/m2 and temperature 600 C? (a) 7.72 x 10 (b) 3.86 x 106 (c) 2.65 x 106 (d) 641 (e) 441 (5) The average molecular kinetic energy of a gas can be determined by knowing only (a) the temperature of the gas. (b) the volume of the gas. (c) the number of molecules in the gas. (d) the pressure of the gas (e) all of the above must be known. (6) A liquid boils when its vapor pressure (a) equals the external pressure. (b) equals the equilibrium vapor pressure. (c) is between the equilibrium vapor pressure and the external pressure. (d) exceeds the external pressure. (e) None of the other choices is correct. (7) The root-mean-square speed of the molecules of a gas is 200 m/s at a temperature 300 K. What is the mass of the individual molecules? (a) 1.78 x 10 kg (b) 3.11 x 1025kg (c) 2.13 x 10 kg (d) 5.66 x 10 kg (e) 2.45 x 1025 kg Page 1Explanation / Answer
Solution:
1) Ans : [a]Increases.
Reason: When water is heated from 0 0C, its volume decreases because its density increases and you can see this effect upto 4 0C.
2.) Ans: [d] Isochoric or isometric.
Reason: As volume is contant in this process. so the work done is zero.
3.)Asn: [c] Is same for all the substance.
Reason: Number of molecues in 1mole of any substance is Na[Avegadro number].
4.) Ans: [e]441.
Reason:Using ideal gas equation,
n = PV/RT = 8*105*4/[8.314*(600+273K)]
n = 440.88 = 441 mol.
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