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l Grameenphone 3G @ 76% 10:11 AM oldcmos.iub.edu.bd Date of Submission: Assignme

ID: 2303629 • Letter: L

Question

l Grameenphone 3G @ 76% 10:11 AM oldcmos.iub.edu.bd Date of Submission: Assignment 02 On or Before 24th July, 2018 Magnetic Field I. If a proton moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the proton and the frequency of motion? 2. An electron at point A has a speed v10'm/s. Find (a) The magnitude and the direction of the magnetic field that will cause the electron to follow the semicircular path from point A to B. (b) The time require to move the electron from A to B. [The mass of the electron is 9.31 103 kg and the charge of the electron is -1.61 10-19 C . An electron at point A has a speed v10'm/s. Find (a) The magnitude and the direction of the magnetic field that will cause the electron to follow the semicircular path from point A to B. (b) The time require to move the electron from A to B. (c) Repeat the problem by considering a proton now. [The mass of the electron and proton are 9.11 1031 kg and 1.67 1027 kg respectively and the charge of the electron & proton is 1.61 1019 C] 4 A solenoid is 30 cm long and is wound with two layers of wire. The inner layer consists of 300 turns, the outer layers of 250 turns. The current is 3A in the same direction in both layers. What is the magnetic field at a point near the solenoid? What is the magnetic field if the current flows in the opposite direction in different layer? s A long straight wire carries a current 1.5 A. An electron travels with a speed of 5.0 10 cm/s, parallel to the wire, 10cm from it and in the same direction as the current. What force does the magnetic field exert on the moving electron? A closely wound coil has a diameter of 40cm and carries a current 2.5 A. How many turns does it have if the magnetic field at the center of the coil is 1.26 104 T? . A solenoid is to be designed to produce a magnetic field of 0.1 T at its center. The radius is to be 5 cm and the length is 50 cm and the available wire can carry a

Explanation / Answer

1) magentic force = centripetal force

qvB = mv^2 / r

v = qBr/m

= 1.6*10^-19*0.4*0.21 / 1.67*10^-27

= 8*10^6 m/s

frequency = v/2pi*r

= 8*10^6 / 2pi*0.21

= 6.1*10^6 Hz