suppose you have three particles, and three state distinct one particle States,
ID: 2303830 • Letter: S
Question
suppose you have three particles, and three state distinct one particle States, wave function a, wave function B, and wave function C are available. How many three particle States can be constructed,
a. if they are distinguishable particles,
b. if they are identical bosons,
c. if they are identical fermions?
Explanation / Answer
A. if they are distinguishable particles then we can construct 3! = 6 states ( assuming that no state has more than 2 particles)
they are 1,2,3 ; 1,3,2 ; 2,1,3 ; 2,3,1 ; 3, 1,2 ; 3,2,1
B. if they are fermions we can construct only one state(because they are identical and no state can have 2 or more particles)
C. if they are boson we can arrange as our wish( we can even keep all particles in one state) so number of wars are
all 3 particles occpying same state - we have 3 possiblities
2 particles occpying same state - we have 3C2 possibilies = 3
no 2 particles occpying same state = we have 1 possiblities
so total number of ways we can construct three particle States for bosans is 3+3+1 = 7
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