In the figure, a metal wire of mass m 28.9 mg can slide with negligible friction

Question

In the figure, a metal wire of mass m 28.9 mg can slide with negligible friction on two horizontal parallel rails separated by distance d 1.81 cm. The track lies in a vertical uniform magnetic field of magnitude 57.4 mT. At time t 0 s, device G is connected to the rails, producing a constant current i 9.82 mA in the wire and rails (even as the wire moves). At t- 41.6 ms, what are the wire's (a) speed and (b) direction of motion? IL (a) Number To.0014685794 ? (b)Tothe left the tolerance is +/-790

Explanation / Answer

The magnetic force on wire is Fb = i d B pointing to the left.

So, v = at = Fb t/ m = i d B t/ m

v = (9.82 x 10-3 x 0.0181 x 57.4 x 10-3 x 41.6 x 10-3)/ 0.0289 = 1.468 x 10-5 m/s

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