Pad 11:20 AM 11*92% & edugen.wileyplus.com ASSIGNMENT RESOURCES Homework 22 Chap

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Pad 11:20 AM 11*92% & edugen.wileyplus.com ASSIGNMENT RESOURCES Homework 22 Chapter 29, Problem 35 Chapter 29 Probl An electron, starting from rest, accelerates through a potential difference of 637 V. What is the final de Broglie wavelength of the electron, assuming that its final speed is much less than the speed of light? Number Units GO the tolerance is +/-5% Chapter 29, Problem 26 SHOW HI GO LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Review Score Review Results by Study Objective Question Attempts: 0 of 3 used SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

here,

potential difference , V = 637 V

let the speed of electron be v

using conservation of energy

the work done = kinetic energy gained

V * e = 0.5 * m * v^2

637 * 1.6 * 10^-19 = 0.5 * 9.1 * 10^-31 * v^2

solving for v

v = 1.5 * 10^7 m/s

the wavelength of electron , lamda = h/mv

lamda = 6.634 * 10^-34 /( 9.1 * 10^-31 * 1.5 * 10^7) m

lamda = 4.86 * 10^-11 m

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